Optimal. Leaf size=125 \[ \frac {\sqrt {\sqrt {a}+\sqrt {b}} \tan ^{-1}\left (\frac {\sqrt {\sqrt {a}+\sqrt {b}} \tan (c+d x)}{\sqrt [4]{a}}\right )}{2 a^{3/4} \sqrt {b} d}-\frac {\sqrt {\sqrt {a}-\sqrt {b}} \tan ^{-1}\left (\frac {\sqrt {\sqrt {a}-\sqrt {b}} \tan (c+d x)}{\sqrt [4]{a}}\right )}{2 a^{3/4} \sqrt {b} d} \]
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Rubi [A] time = 0.11, antiderivative size = 125, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.125, Rules used = {3224, 1093, 205} \[ \frac {\sqrt {\sqrt {a}+\sqrt {b}} \tan ^{-1}\left (\frac {\sqrt {\sqrt {a}+\sqrt {b}} \tan (c+d x)}{\sqrt [4]{a}}\right )}{2 a^{3/4} \sqrt {b} d}-\frac {\sqrt {\sqrt {a}-\sqrt {b}} \tan ^{-1}\left (\frac {\sqrt {\sqrt {a}-\sqrt {b}} \tan (c+d x)}{\sqrt [4]{a}}\right )}{2 a^{3/4} \sqrt {b} d} \]
Antiderivative was successfully verified.
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Rule 205
Rule 1093
Rule 3224
Rubi steps
\begin {align*} \int \frac {\cos ^2(c+d x)}{a-b \sin ^4(c+d x)} \, dx &=\frac {\operatorname {Subst}\left (\int \frac {1}{a+2 a x^2+(a-b) x^4} \, dx,x,\tan (c+d x)\right )}{d}\\ &=\frac {(a-b) \operatorname {Subst}\left (\int \frac {1}{a-\sqrt {a} \sqrt {b}+(a-b) x^2} \, dx,x,\tan (c+d x)\right )}{2 \sqrt {a} \sqrt {b} d}-\frac {(a-b) \operatorname {Subst}\left (\int \frac {1}{a+\sqrt {a} \sqrt {b}+(a-b) x^2} \, dx,x,\tan (c+d x)\right )}{2 \sqrt {a} \sqrt {b} d}\\ &=-\frac {\sqrt {\sqrt {a}-\sqrt {b}} \tan ^{-1}\left (\frac {\sqrt {\sqrt {a}-\sqrt {b}} \tan (c+d x)}{\sqrt [4]{a}}\right )}{2 a^{3/4} \sqrt {b} d}+\frac {\sqrt {\sqrt {a}+\sqrt {b}} \tan ^{-1}\left (\frac {\sqrt {\sqrt {a}+\sqrt {b}} \tan (c+d x)}{\sqrt [4]{a}}\right )}{2 a^{3/4} \sqrt {b} d}\\ \end {align*}
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Mathematica [A] time = 0.28, size = 158, normalized size = 1.26 \[ \frac {\frac {\left (\sqrt {a} \sqrt {b}+b\right ) \tan ^{-1}\left (\frac {\left (\sqrt {a}+\sqrt {b}\right ) \tan (c+d x)}{\sqrt {\sqrt {a} \sqrt {b}+a}}\right )}{\sqrt {\sqrt {a} \sqrt {b}+a}}+\frac {\left (\sqrt {a} \sqrt {b}-b\right ) \tanh ^{-1}\left (\frac {\left (\sqrt {a}-\sqrt {b}\right ) \tan (c+d x)}{\sqrt {\sqrt {a} \sqrt {b}-a}}\right )}{\sqrt {\sqrt {a} \sqrt {b}-a}}}{2 \sqrt {a} b d} \]
Antiderivative was successfully verified.
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fricas [B] time = 0.56, size = 541, normalized size = 4.33 \[ -\frac {1}{8} \, \sqrt {-\frac {a b d^{2} \sqrt {\frac {1}{a^{3} b d^{4}}} + 1}{a b d^{2}}} \log \left (\frac {1}{2} \, a d \sqrt {-\frac {a b d^{2} \sqrt {\frac {1}{a^{3} b d^{4}}} + 1}{a b d^{2}}} \cos \left (d x + c\right ) \sin \left (d x + c\right ) + \frac {1}{4} \, \cos \left (d x + c\right )^{2} + \frac {1}{4} \, {\left (2 \, a^{2} d^{2} \cos \left (d x + c\right )^{2} - a^{2} d^{2}\right )} \sqrt {\frac {1}{a^{3} b d^{4}}} - \frac {1}{4}\right ) + \frac {1}{8} \, \sqrt {-\frac {a b d^{2} \sqrt {\frac {1}{a^{3} b d^{4}}} + 1}{a b d^{2}}} \log \left (-\frac {1}{2} \, a d \sqrt {-\frac {a b d^{2} \sqrt {\frac {1}{a^{3} b d^{4}}} + 1}{a b d^{2}}} \cos \left (d x + c\right ) \sin \left (d x + c\right ) + \frac {1}{4} \, \cos \left (d x + c\right )^{2} + \frac {1}{4} \, {\left (2 \, a^{2} d^{2} \cos \left (d x + c\right )^{2} - a^{2} d^{2}\right )} \sqrt {\frac {1}{a^{3} b d^{4}}} - \frac {1}{4}\right ) + \frac {1}{8} \, \sqrt {\frac {a b d^{2} \sqrt {\frac {1}{a^{3} b d^{4}}} - 1}{a b d^{2}}} \log \left (\frac {1}{2} \, a d \sqrt {\frac {a b d^{2} \sqrt {\frac {1}{a^{3} b d^{4}}} - 1}{a b d^{2}}} \cos \left (d x + c\right ) \sin \left (d x + c\right ) - \frac {1}{4} \, \cos \left (d x + c\right )^{2} + \frac {1}{4} \, {\left (2 \, a^{2} d^{2} \cos \left (d x + c\right )^{2} - a^{2} d^{2}\right )} \sqrt {\frac {1}{a^{3} b d^{4}}} + \frac {1}{4}\right ) - \frac {1}{8} \, \sqrt {\frac {a b d^{2} \sqrt {\frac {1}{a^{3} b d^{4}}} - 1}{a b d^{2}}} \log \left (-\frac {1}{2} \, a d \sqrt {\frac {a b d^{2} \sqrt {\frac {1}{a^{3} b d^{4}}} - 1}{a b d^{2}}} \cos \left (d x + c\right ) \sin \left (d x + c\right ) - \frac {1}{4} \, \cos \left (d x + c\right )^{2} + \frac {1}{4} \, {\left (2 \, a^{2} d^{2} \cos \left (d x + c\right )^{2} - a^{2} d^{2}\right )} \sqrt {\frac {1}{a^{3} b d^{4}}} + \frac {1}{4}\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [B] time = 0.93, size = 559, normalized size = 4.47 \[ \frac {\frac {{\left (3 \, \sqrt {a^{2} - a b + \sqrt {a b} {\left (a - b\right )}} a^{2} b - 6 \, \sqrt {a^{2} - a b + \sqrt {a b} {\left (a - b\right )}} a b^{2} - \sqrt {a^{2} - a b + \sqrt {a b} {\left (a - b\right )}} b^{3} - 3 \, \sqrt {a^{2} - a b + \sqrt {a b} {\left (a - b\right )}} \sqrt {a b} a^{2} + 6 \, \sqrt {a^{2} - a b + \sqrt {a b} {\left (a - b\right )}} \sqrt {a b} a b + \sqrt {a^{2} - a b + \sqrt {a b} {\left (a - b\right )}} \sqrt {a b} b^{2}\right )} {\left (\pi \left \lfloor \frac {d x + c}{\pi } + \frac {1}{2} \right \rfloor + \arctan \left (\frac {2 \, \tan \left (d x + c\right )}{\sqrt {\frac {4 \, a + \sqrt {-16 \, {\left (a - b\right )} a + 16 \, a^{2}}}{a - b}}}\right )\right )} {\left | a - b \right |}}{3 \, a^{5} b - 12 \, a^{4} b^{2} + 14 \, a^{3} b^{3} - 4 \, a^{2} b^{4} - a b^{5}} + \frac {{\left (3 \, \sqrt {a^{2} - a b - \sqrt {a b} {\left (a - b\right )}} a^{2} b - 6 \, \sqrt {a^{2} - a b - \sqrt {a b} {\left (a - b\right )}} a b^{2} - \sqrt {a^{2} - a b - \sqrt {a b} {\left (a - b\right )}} b^{3} + 3 \, \sqrt {a^{2} - a b - \sqrt {a b} {\left (a - b\right )}} \sqrt {a b} a^{2} - 6 \, \sqrt {a^{2} - a b - \sqrt {a b} {\left (a - b\right )}} \sqrt {a b} a b - \sqrt {a^{2} - a b - \sqrt {a b} {\left (a - b\right )}} \sqrt {a b} b^{2}\right )} {\left (\pi \left \lfloor \frac {d x + c}{\pi } + \frac {1}{2} \right \rfloor + \arctan \left (\frac {2 \, \tan \left (d x + c\right )}{\sqrt {\frac {4 \, a - \sqrt {-16 \, {\left (a - b\right )} a + 16 \, a^{2}}}{a - b}}}\right )\right )} {\left | a - b \right |}}{3 \, a^{5} b - 12 \, a^{4} b^{2} + 14 \, a^{3} b^{3} - 4 \, a^{2} b^{4} - a b^{5}}}{2 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.58, size = 226, normalized size = 1.81 \[ \frac {a \arctanh \left (\frac {\left (-a +b \right ) \tan \left (d x +c \right )}{\sqrt {\left (\sqrt {a b}-a \right ) \left (a -b \right )}}\right )}{2 d \sqrt {a b}\, \sqrt {\left (\sqrt {a b}-a \right ) \left (a -b \right )}}-\frac {a \arctan \left (\frac {\left (a -b \right ) \tan \left (d x +c \right )}{\sqrt {\left (\sqrt {a b}+a \right ) \left (a -b \right )}}\right )}{2 d \sqrt {a b}\, \sqrt {\left (\sqrt {a b}+a \right ) \left (a -b \right )}}-\frac {b \arctanh \left (\frac {\left (-a +b \right ) \tan \left (d x +c \right )}{\sqrt {\left (\sqrt {a b}-a \right ) \left (a -b \right )}}\right )}{2 d \sqrt {a b}\, \sqrt {\left (\sqrt {a b}-a \right ) \left (a -b \right )}}+\frac {b \arctan \left (\frac {\left (a -b \right ) \tan \left (d x +c \right )}{\sqrt {\left (\sqrt {a b}+a \right ) \left (a -b \right )}}\right )}{2 d \sqrt {a b}\, \sqrt {\left (\sqrt {a b}+a \right ) \left (a -b \right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ -\int \frac {\cos \left (d x + c\right )^{2}}{b \sin \left (d x + c\right )^{4} - a}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 15.66, size = 1409, normalized size = 11.27 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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